Wednesday, August 5, 2009

TEST--54--XI [state of matter]

Q.2.
The vapour density of pure ozone is
[a] 16 [b] 24 [c] 32 [d] 48

5 comments:

  1. ans.[b]-24
    Molecular weight=2*Vapour Density
    Hence,
    =Molecular weight of ozone=2*its vapour density
    =3*Atomic weight of Oxygen=2*VD
    =3(16)=2(VD)
    therefore,by the calculations,we get VD=24

    ReplyDelete
  2. The answer is [b] because molecular weight/2=V.D. Molecular weight of ozone is 48.Thus V.D= 24.

    ReplyDelete
  3. b 24
    molecular weight = 2*vd
    48 = 2*vd...as mw of ozon is 48
    vd of ozon =24

    ReplyDelete