Monday, August 3, 2009

TEST--54--XI [state of matter]

Q-1-
Mass of 112 ml nitrogen at STP will be
[a] 0.28 g [b] 28 g [c] 14 g [d] 0.14 g
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6 comments:

  1. Akshay PatwardhanAugust 3, 2009 at 9:59 PM

    ans.[d]0.14g.
    22.4dm3=Molecular weight of Nitrogen(i.e-28g.)
    Hence,22.4*10*10*10ml/112ml=28g/x g.
    by calculating,we get,x=0.14g

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  2. Akshay PatwardhanAugust 3, 2009 at 10:05 PM

    ans.[d]0.14g
    22.4dm3 of Nitrogen=Molecular weight of Nitrogen(i.e-28)
    Hence,22.4*10*10*10ml/112ml=28g/x g.
    By Calculating,we get,x=0.14g.

    ReplyDelete
  3. UnknownAugust 3, 2009 at 10:21 PM

    The answer is [d] because 22.4 L nitrogen will contain 28 g of nitrogen.Similarly 112 ml (0.112 L) nitrogen will contain 0.14 g of nitrogen.

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  4. UnknownAugust 3, 2009 at 10:34 PM

    Q 1- c

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  5. UnknownAugust 4, 2009 at 8:54 PM

    answer-d

    ReplyDelete
  6. UnknownAugust 7, 2009 at 9:30 PM

    d

    ReplyDelete

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